Very simple inorganic chemical reaction HELP

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SUMMARY

The chemical reaction between potassium bromide (KBr) and sodium hydroxide (NaOH) results in the formation of potassium hydroxide (KOH) and sodium bromide (NaBr). This reaction is classified as a double displacement reaction. In a boiling solution of NaOH, both KBr and NaOH dissociate into their respective ions, leading to the products KOH and NaBr. It is important to note that due to the high solubility of the reactants and products, no visible reaction may be observed.

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  • Understanding of double displacement reactions
  • Knowledge of ionic dissociation in aqueous solutions
  • Familiarity with chemical equation balancing
  • Basic concepts of solubility and reaction visibility
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  • Study the principles of double displacement reactions in inorganic chemistry
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stamba
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Hello.
Can you please help me with this reaction?

* KBr + NaOH --> ?*

Put KBr in boilling solution of NaOH. What are the products?
 
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If I'm not mistaken sorry if I'm wrong on this but I think it should be

KBr + NaOH --> KOH+ NaBr
 
However, all of those will dissociate into ions (on both sides of the equation). Maybe you have to assume that water is a reagant because it is a solution of NaOH, and then it will be an acidic reaction. I may be off though...
 
Maybe you'll observe no visible reaction since both the reactants and products are very soluble. But it should be a simple double displacement reaction I think
 

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