Products of KBr heated in boiling NaOH solution

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stamba
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Hello.
Can you please help me with this reaction?

* KBr + NaOH --> ?*

Put KBr in boilling solution of NaOH. What are the products?
 
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If I'm not mistaken sorry if I'm wrong on this but I think it should be

KBr + NaOH --> KOH+ NaBr
 
However, all of those will dissociate into ions (on both sides of the equation). Maybe you have to assume that water is a reagant because it is a solution of NaOH, and then it will be an acidic reaction. I may be off though...
 
Maybe you'll observe no visible reaction since both the reactants and products are very soluble. But it should be a simple double displacement reaction I think