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f(x) = aX^{0}is the form of any constant polynomial... right??

eg: f(x) = 3 is actually f(x) =3X^{0}where X belongs to R... ok??

since 0^{0}is an unspecified quantity.. therefore on graphing a constant.. it should exists a hole on y-axis... and the y-intercept should not satisfy the function ie: excluded from the solution set. am I right.. HELP

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# Very strange about the zero degree polynomial

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