What does it mean when I have to find the second derivative of a circle at a given point? (Implicit diffing)(adsbygoogle = window.adsbygoogle || []).push({});

In specifics, the equation is 9x^{2}+y^{2}=9

At the point (0,3)

You don't really need the rest at all, but it was just my process.

This seems to make no sense.

first D'v 18x+2yy^{'}=0

Second derivative gives 18+y^{''}=0

Doesn't it?

How am I supposed to substitute coordinates?

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# Very very short question on second derivative

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