Vibrational Motion - Calculating Mean Square Displacement

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The discussion focuses on calculating the mean square displacement of a particle from its equilibrium position using a specific integral involving Hermite polynomials. The user expresses confusion over the application of recursion relations in their calculations and the behavior of odd and even Hermite polynomials. They note that integrating an odd function over a symmetrical range results in zero, which raises concerns about the validity of their results. The user seeks clarification on the mathematical steps involved, particularly regarding the relationship between variables and the use of recursion in the integral. The conversation emphasizes the importance of understanding the properties of Hermite polynomials in solving the problem correctly.
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Homework Statement


Calculate the mean square displacement x2 of the particle from its
equilibrium position.

Homework Equations


∫ from -\infty to +\infty of Nv2 * Hv(y) * e-y^2 dy

Since y=x/\alpha, \alphady=dx

yHv = vHv-1 + (1/2)Hv+1

The Attempt at a Solution


https://www.dropbox.com/s/uiqbgzjjlqnnqwk/2014-02-14%2022.23.41.jpg

What is boxed is where I distributed everything. That looked horrible so I applied the recursion relation once. I believe the last integral goes to zero. Integrating an odd function over a symmetrical range would be zero. But then everything would be zero and that's just wrong. There should be a relationship between v and m and kf and hbar from \alpha. I apologize, but please explain the math as simple as possible. The math is the issue, not really the concept.

EDIT: Should I apply the recursion relation once more in the integral as it has yHv?
 
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I don't know that much about Hermite polynomials to judge your calculations but what I know is that they are alternating in being odd and even.In fact even numbered ones are even and odd numbered ones are odd.
Take this into account when calculating the integral!
 

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