Vijay's Reflex Time When Arvind Drops a Scale

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SUMMARY

The discussion centers around calculating Vijay's reflex time when he catches a scale dropped by Arvind, which slips 20 cm during the fall. The relevant kinematic equation for constant acceleration is identified as d = vit + ½at2, where the initial velocity (vi) is zero and acceleration (a) is 9.81 m/s2. Participants emphasize the importance of using the correct forum for questions, suggesting that this topic is more suited for the homework forum. The conversation highlights the need for understanding kinematic equations to solve problems involving constant acceleration.

PREREQUISITES
  • Understanding of kinematic equations for constant acceleration
  • Basic knowledge of physics concepts, specifically gravity (9.81 m/s2)
  • Familiarity with displacement and its relation to time and acceleration
  • Ability to identify appropriate forums for academic questions
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  • Study the kinematic equations in detail, focusing on their applications
  • Practice problems involving constant acceleration and reflex time calculations
  • Explore the concept of gravitational acceleration and its effects on falling objects
  • Learn how to properly categorize questions in academic forums for better assistance
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Students studying physics, particularly those learning about kinematics and constant acceleration, as well as individuals seeking to improve their problem-solving skills in physics-related scenarios.

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arvind drops a scale vertically which is grabbed by Vijay whose hand is just below the scale. In the mean time the scale slips by 20cm. What is the reflex time of Vijay?
 
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Do you know any equations that may help you here? (hint: constant acceleration).

Is there a reason why this is in the tutorial forum? In future please post in the homework forum.
 
cristo said:
Do you know any equations that may help you here? (hint: constant acceleration).

Is there a reason why this is in the tutorial forum? In future please post in the homework forum.

yes, the acceleration will be 9.8 m/sec^2. But how will this help?

oh! I am sorry once again. I haven't understood till now, as to which question should I post in which section. I am sorry again.
 
ritwik06 said:
yes, the acceleration will be 9.8 m/sec^2. But how will this help?

Correct. Do you know any equations that will help you here? You are told the displacement, and you know that the initial velocity is zero.

oh! I am sorry once again. I haven't understood till now, as to which question should I post in which section. I am sorry again.

That's ok. I'm sure it'll be moved for you soon anyway! In future though, use the homework forum. It's the second forum in the list on the front page (just under the tutorial forum)
 
cristo said:
Correct. Do you know any equations that will help you here? You are told the displacement, and you know that the initial velocity is zero.



That's ok. I'm sure it'll be moved for you soon anyway! In future though, use the homework forum. It's the second forum in the list on the front page (just under the tutorial forum)

Nope which equation are you talking about?

Ok! I will use the homework section. Thanks!

sorry once again.
 
Have you come across the kinematic equations, for constant acceleration? Here's a link to them (scroll about half way down the page): http://www.glenbrook.k12.il.us/GBSSCI/PHYS/Class/1DKin/U1L6a.html . Which one do you think is most useful in this case?
 
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cristo said:
Have you come across the kinematic equations, for constant acceleration? Here's a link to them (scroll about half way down the page): http://www.glenbrook.k12.il.us/GBSSCI/PHYS/Class/1DKin/U1L6a.html . Which one do you think is most useful in this case?

will the 3rd one help? I have not studdied kinematics yet :S
 
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ritwik06 said:
will the 3rd one help? I have not studdied kinematics yet :S

Ok, well you should use the first equation:d=v_it+\frac{1}{2}at^2. Here, note that vi=0, so this simplifies the equation somewhat. a is the acceleration due the gravity (9.81), d is the distance measured on the ruler, and t is the reaction time that you require.
 
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