#### yellowcakepie

**1. Homework Statement**

A scale is adjusted so that when a large, shallow pan is placed on it, it reads zero. A water faucet at height h = 4.0 m above is turned on and water falls into the pan at a rate R = 0.20 kg/s.

A) Determine a formula for the scale reading as a function of time t if at the moment t=0 first drops of water reach the pan.

B) Determine the reading for t = 9.4 s.

C) Repeat part B, but replace the shallow pan with a tall, narrow cylindrical container of area A = 18 cm^2 (the level rises in this case).

**2. Homework Equations**

Δx = 0.5gt^2

v = gt

I = R*v

F(t) = I + Rgt

**3. The Attempt at a Solution**

I have already solved parts A and B, but I am having trouble with part C.

A) F(t) = R√(2h/g)*g + Rgt (force due to change of momentum of the water plus weight of water in the container)

B) F(9.4 s) = 20 N

C) I have A = 0.0018 m^2 area for the cylindrical container, and density of water (D) is 1000 kg/m^3, so I got the fill rate by dividing D/R, and then divided A by D/R to get the change in height per second, which is 0.11 m/s.

I have no clue how to incorporate this height change rate into my answer.

Last edited by a moderator: