- #1
2Tesla
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- 0
Why are virtual photons and gravitons allowed to pass outwards through the event horizon of a black hole? Is it that it doesn't really make sense to assign a particular path to a virtual photon? This still isn't satisfying to me, as there is *no* path that allows a real photon to escape.
Further confusing me on this issue, part of the Hawking radiation process is for one of a virtual pair of particles to fall into the black hole and be trapped there. Why is that virtual particle trapped, while a virtual photon is free to escape?
And, if I can slip one more question into this already-crowded post: I've heard, as supposed proof for charge, mass and spin being exceptions to the no-hair rule, the fact that charge, energy and angular momentum wouldn't be conserved if these three characteristics were lost (radiated). This doesn't seem right to me, since I can put a charged object inside a shielded box and not violate conservation of charge. Is the real reason just that they can't be radiated?
(If people would prefer it, I can move these questions (or just the last one) over to the GR board.)
Further confusing me on this issue, part of the Hawking radiation process is for one of a virtual pair of particles to fall into the black hole and be trapped there. Why is that virtual particle trapped, while a virtual photon is free to escape?
And, if I can slip one more question into this already-crowded post: I've heard, as supposed proof for charge, mass and spin being exceptions to the no-hair rule, the fact that charge, energy and angular momentum wouldn't be conserved if these three characteristics were lost (radiated). This doesn't seem right to me, since I can put a charged object inside a shielded box and not violate conservation of charge. Is the real reason just that they can't be radiated?
(If people would prefer it, I can move these questions (or just the last one) over to the GR board.)