Viscosity of Water: Calculating Temperature-Dependent Flow

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To calculate the viscosity of water at 350K, the user initially struggled to find relevant equations and data. They discovered that the viscosity of water at 300K is 86.0 x 10^-5 Pa*s and sought guidance on how to convert viscosity measurements from kg/m*s to Pa*s. The discussion clarified that dynamic viscosity and kinematic viscosity are different, with dynamic viscosity being the required measurement. The user ultimately found the necessary information online and expressed gratitude for the assistance. Understanding the relationship between viscosity units helped resolve their confusion.
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Homework Statement



Hi guys, I need to find the flow of water at temperature of 350K. I had to do this, but for air in the same problem...but I can't find an equation to account for the viscosity change, due to temperature rise. My book lists it at 86.0 x 10^-5 Pa*s @ temp 300K.

Homework Equations





The Attempt at a Solution



I've searched the web for some time now, and can't find any equations for water. Any help would be great.

Thanks,
Brad
 
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Bradracer18 said:
I've searched the web for some time now, and can't find any equations for water.

Google for "viscosity water temperature".
 
Ok, so I found the page(thanks)...and the first link takes me right to what I need. But...the viscosity is dynamic(is that the same as just plain viscosity?)...and also, they have it measured in kg/m*s and I need it measured in Pa*s. Again, I've looked in my book and on the net, and I can't find out how you convert between those two.

The only conversion that I found(and I don't think it works)...but its 1kg(force)/m^2 = 9.806650 Pa.
 
Does anyone know about these conversions...?
 
1 Pascal (Pa) is 1 Newton/m^2

1 Newton (N) is the force to accelerate 1 Kg at 1 m/s^2

So 1 Pa.s = 1 N.s/m^2 = 1 (Kg.m/s^2).(s/m^2) = 1 Kg/(m.s)

BTW There are two different units for viscosity, dynamic and kinematic. Kinematic viscosity = dynamic viscosity / density. The one you want is dynamic viscosity.
 
Oh ok...so they are the same units then(or equivilant)...I guess I didn't put to much time into it, seems pretty obvious now, duh. ha. Well thanks though, I really appreciate you showing me the right direction!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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