Viscosity of Water: Calculating Temperature-Dependent Flow

  • Thread starter Thread starter Bradracer18
  • Start date Start date
  • Tags Tags
    Viscosity Water
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
5 replies · 9K views
Bradracer18
Messages
203
Reaction score
0

Homework Statement



Hi guys, I need to find the flow of water at temperature of 350K. I had to do this, but for air in the same problem...but I can't find an equation to account for the viscosity change, due to temperature rise. My book lists it at 86.0 x 10^-5 Pa*s @ temp 300K.

Homework Equations





The Attempt at a Solution



I've searched the web for some time now, and can't find any equations for water. Any help would be great.

Thanks,
Brad
 
Physics news on Phys.org
Ok, so I found the page(thanks)...and the first link takes me right to what I need. But...the viscosity is dynamic(is that the same as just plain viscosity?)...and also, they have it measured in kg/m*s and I need it measured in Pa*s. Again, I've looked in my book and on the net, and I can't find out how you convert between those two.

The only conversion that I found(and I don't think it works)...but its 1kg(force)/m^2 = 9.806650 Pa.
 
Does anyone know about these conversions...?
 
1 Pascal (Pa) is 1 Newton/m^2

1 Newton (N) is the force to accelerate 1 Kg at 1 m/s^2

So 1 Pa.s = 1 N.s/m^2 = 1 (Kg.m/s^2).(s/m^2) = 1 Kg/(m.s)

BTW There are two different units for viscosity, dynamic and kinematic. Kinematic viscosity = dynamic viscosity / density. The one you want is dynamic viscosity.
 
Oh ok...so they are the same units then(or equivilant)...I guess I didn't put to much time into it, seems pretty obvious now, duh. ha. Well thanks though, I really appreciate you showing me the right direction!