Visualizing the plane, 1x+1y+1z = 0

  • Context: Undergrad 
  • Thread starter Thread starter Ocata
  • Start date Start date
  • Tags Tags
    Plane
Click For Summary
SUMMARY

The discussion focuses on visualizing the plane represented by the equation x + y + z = 0. Participants highlight the challenge of understanding the traces of this plane, which intersect only at the origin, unlike other equations such as x + y + z = 1 that form distinct geometric shapes. Key insights include the importance of plotting traces in the coordinate planes and calculating additional points to better visualize the plane's structure. The value of understanding that d = 0 indicates the plane passes through the origin is also emphasized.

PREREQUISITES
  • Understanding of three-dimensional geometry
  • Familiarity with linear equations and their graphical representations
  • Basic knowledge of intercepts in coordinate systems
  • Ability to use graphing tools such as Wolfram Alpha
NEXT STEPS
  • Learn how to graph planes in three-dimensional space using software tools
  • Explore the concept of traces in different coordinate planes
  • Study the implications of the constant term d in plane equations
  • Investigate the differences between parallel planes and their intersections
USEFUL FOR

Students and educators in mathematics, particularly those studying geometry and linear algebra, as well as anyone interested in visualizing three-dimensional equations.

Ocata
Messages
198
Reaction score
5
Hello,

I made traces for the equation, x+y+z=0, but they don't seem to connect in an intuitive way as other equations do. For instance, even with x+y+z=1, I can make traces where the 3 lines connect to make a triangle in the first/positive quadrant. But x+y+z=0 has traces that all run through the origin. Not sure how to draw/connect traces for a plane whose traces seem to only intersect at the origin.
 
Physics news on Phys.org
Ocata said:
Hello,

I made traces for the equation, x+y+z=0, but they don't seem to connect in an intuitive way as other equations do. For instance, even with x+y+z=1,
x + y + z = 1 is a different plane than x + y + z = 0. The two planes are parallel, though, but don't share any points.
Ocata said:
I can make traces where the 3 lines connect to make a triangle in the first/positive quadrant. But x+y+z=0 has traces that all run through the origin. Not sure how to draw/connect traces for a plane whose traces seem to only intersect at the origin.
The origin is a point on your plane. It might help to draw traces in the three coordinate planes. For example, in the x-y plane (where z = 0), the trace is the line x + y = 0, or equivalently, the line y = -x.

To get a three-dimensional view of this plane, calculate two points other than the origin (which is on the plane). Those three points should give you some idea of how the plane looks.
 
  • Like
Likes   Reactions: Ocata
Thank you Spinner,

I did graph it on paper but it still didn't make sense because I was tracing through the intercepts and I wasn't able to get a clear idea of the plane. In the equation, d = 0. Now I see that d = 0 implied the plane goes through the origin. Thank you.
 
Thank you Mark44.

I have a clear visualization of x + y + z = 0. Your first statement sealed the deal visually for me. Your suggestion to calculate points other than the origin allowed me to realize I can find intercepts other than 0 + y = 0, x + 0 = 0, and z + 0 = 0.

Thank you.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K