Voltage of a Capacitor using Kirchhoff's Loop Rule

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SUMMARY

The discussion focuses on using Kirchhoff's Loop Rule to determine the voltages across five capacitors in a given network. The user presents a set of equations derived from Kirchhoff's laws, specifically addressing the relationships between charge and voltage across capacitors. Key equations include the relationships for voltage and charge, such as ## -V_1 - V_5 - V_2 + V_A = 0## and ## -Q_5 + Q_4 + Q_2= 0##. The conversation emphasizes the need for a systematic approach to solving the equations and the importance of identifying multiple loops in the circuit for a comprehensive analysis.

PREREQUISITES
  • Understanding of Kirchhoff's Loop Rule and Junction Law
  • Familiarity with capacitor equations, specifically C = q/v
  • Basic knowledge of circuit analysis techniques
  • Proficiency in using mathematical software like Mathematica for solving systems of equations
NEXT STEPS
  • Explore advanced techniques for solving systems of equations in circuit analysis
  • Learn about the application of Kirchhoff's laws in complex circuits
  • Investigate the use of matrix methods for circuit analysis
  • Study the impact of varying capacitance values on circuit behavior
USEFUL FOR

Students in physics or electrical engineering, circuit designers, and anyone involved in analyzing electrical networks using Kirchhoff's laws.

unknownv2
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(Sorry, meant to post this in Introductory Physics Homework, if someone could please move it.)


1. Homework Statement


Use Kirchhoff's Loop Rule to solve for the voltages of the five capacitors in the network shown below.

Z36ydF0.jpg

Homework Equations



For Capacitance, C = q/v
Kirchoff's juction law states that the total current into a junction must equal the total current leaving the function and that the sum of the potential differences around any loop or closed path is zero.

08d7bd7060be987d4da37b7fc263a740.png


The Attempt at a Solution


[/B]
My work can be found here: (Warning large image)

https://i.imgur.com/RMDZrAP.jpg

The solution requires a system of equations to solve and I have:

1) ## -V_1 - V_5 - V_2 + V_A = 0##
2) ## -V_3 - V_5 - V_4 + V_A = 0##
3) ## -Q_5 + Q_4 + Q_2= 0##
4) ## -Q_1 - Q_3 + Q_5= 0##1 and 2 translate to:
1) ##\frac{-Q_1}{C_1} + \frac{-Q_5}{C_5} + \frac{-Q_2}{C_2} + 24 = 0##
2) ##\frac{-Q_3}{C_3} + \frac{-Q_5}{C_5} + \frac{-Q_4}{C_4} + 24 = 0##

It doesn't seem possible to solve those system of equations so I assume I messed up somewhere on creating the equations.Questions:

1) Can an open/close loop be created by the voltage connections on both sides of the capacitor, without necessarily returning to the original entrance of the voltage? Such as, if the voltage enters on the left side, can it leave through the right? I'm thinking enters from left (##V_L##) to ##C_1## through ##C_5## then ##C_4## then out the right (##V_R##) side, as an example?

2) How many equations would be needed for the system of equations? Does that depend on the number of junctions or the number of capacitors? So would I need 5 equations total before I can solve this?
 

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Hello V, welcome to PF :smile: !

You either want to reduce the number of unknowns or increase the number of equations.

As to the first: if you pick the voltage at two smart points you can described all the voltage differences
As to the second: there's more loops to be found than you now mention -- that should also answer your first question: think loops, not paths
 

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