1. The problem statement, all variables and given/known data A galvanometer of resistance 40 Ω requires a current of 10 mA to give a full-scale deflection. A shunt is put in position to convert it to a meter reading up to 1.0 A full-scale deflection. A resistance bobbin, intended to convert the galvanometer to one reading up to 1.0 V full-scale deflection, is now attached to the instrument but the shunt is inadvertently left in position. By considering the potential difference across the bobbin and the meter, calculate the voltage which would produce full-scale deflection of the meter. Answer: 60.4 V. 2. The attempt at a solution V = I R = 10 * 10-3 * 40 = 0.4 V and 1 * 40 = 40 V. Total V = 40.4 V. I know that a galvanometer is an ammeter designed for more accurate measurements of A and a shunt is a low-resistance resistor. But what is a resistance bobbin?