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hsiao
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Homework Statement
"Design a multirange voltmeter capable of full-scale deflection for 20.0V, 50.0V, and 100 V. Assume that the meter movement is a galvanometer that has a resistance of 60.0 ohms and gives a full-scale deflection for a current of 1.00 mA"
Homework Equations
V = IR
Kirchoff's Law's
The Attempt at a Solution
I know that the current through the galvanometer must be 1.00mA, meaning i'll need a large resistor in series with the galvanometer. I would be able to solve this no problem if only one voltage was needed, it is the variable voltages that throw me. So far, I believe i have a voltmeter (galv + large resistor) in parallel with a small resistor (so that most of the current flows through the small). I've attempted kirchhoffs and equating v/r for each voltage, but there are too many variables for me to solve. Help? Thanks in advance
Example of a similar, simpler problem:
"A galvanometer requires a current of 1.5mA for full-scale deflection and has a resistance of 75 ohm, may be used to measure currents of much larger values. Calculate the value of the shunt resistor that enables the meter to be used to measure a current of 1 A and full-scale deflection"
Solution:
V = IR = (75)(1.5x10^-3) = (1-1.5x10^-3)R
R = .113 ohms
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