Rate of change of current with time, galvanometer deflection

[kuruman]

Bingo. Calculate the right side with numbers and you are done.

 

[moenste]

Bingo. Calculate the right side with numbers and you are done.

B = μ₀ n I = 4 π * 10^-7 * 1000 * 4 = 5 * 10^-3 T.
Q = 2000 * (8 * 10^-4) * (5 * 10^-3) / 60 = 1.33 * 10^-4 C

 

[cnh1995]

Q = Φ / R = B A N / R?

Right.

 

[cnh1995]

B = μ₀ n I = 4 π * 10^-7 * 1000 * 4 = 5 * 10^-3 T.
Q = 2000 * (8 * 10^-4) * (5 * 10^-3) / 60 = 1.33 * 10^-4 C

That should be 1.34*10^-4..
Use sensitivity of the galvanometer to find the number of divisions.

 

[moenste]

That should be 1.34*10^-4..
Use sensitivity of the galvanometer to find the number of divisions.

θ = a Q = 2 * 1.34 * 10^-4 = 2.68 * 10^-4.

 

[cnh1995]

θ = a Q = 2 * 1.34 * 10^-4 = 2.68 * 10^-4.

Well, 1.34*10^-4 is the actual charge passed through the galvanometer. You have sensitivity as 2 divisions/ microcoulomb. How would you calculate the no of divisions from this?

 

[moenste]

Well, 1.34*10^-4 is the actual charge passed through the galvanometer. You have sensitivity as 2 divisions/ microcoulomb. How would you calculate the no of divisions from this?

θ = a Q = deflections of the galvanometer.

Update
1.34 * 10^-4 C → 1.34 * 10^-4 / 10^-6 = 134 μC.

134 * 2 = 268. I think this should be right.

 

[cnh1995]

θ = a Q = deflections of the galvanometer.

Update
1.34 * 10^-4 C → 1.34 * 10^-4 / 10^-6 = 134 μC.

134 * 2 = 268. I think this should be right.

Right.