Voltage vs Time Homework: Solve for Approx. Volts

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SUMMARY

The discussion revolves around calculating the approximate voltage from a graph displayed on an oscilloscope, where the VOLTS/DIV setting is 0.5 V and the TIME/DIV setting is 2 s. Participants clarify that the voltage can be determined by counting the number of vertical ticks on the oscilloscope trace, with each tick representing 0.5 V. The correct approach involves recognizing that if the signal is nearly three ticks high, the approximate voltage is 1.5 V (3 ticks x 0.5 V/tick). The time scale is irrelevant to the voltage calculation.

PREREQUISITES
  • Understanding of oscilloscope settings, specifically VOLTS/DIV and TIME/DIV.
  • Basic knowledge of voltage measurement techniques.
  • Familiarity with interpreting graphical data from electronic signals.
  • Ability to perform simple arithmetic operations involving multiplication and division.
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  • Study how to read and interpret oscilloscope waveforms effectively.
  • Learn about voltage scaling and measurement techniques in electronics.
  • Explore the principles of signal processing and analysis.
  • Investigate common mistakes in voltage calculations from graphical data.
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Students in electronics or physics courses, educators teaching voltage measurement, and anyone interested in practical applications of oscilloscopes for signal analysis.

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Homework Statement



Your lab partner is opening and closing the tap switch to turn on and off the voltage from a battery. If you see the following trace on the screen and the VOLTS/DIV knob is set to 0.5 V and the TIME/DIV dial is set to 2s/DIV, you can tell that the voltage of the battery is approximately how many volts?


Homework Equations


No known equations that I know of...



The Attempt at a Solution



Well we know that the y-axis is all together .5 volts, and the x-axis is 2 seconds..so it would common to just multiply .5 by 2..however, it's not one of the choices. So I thought that in the graph since there are three tick marks, you would divide .5/3 and 2/3 and then multiply that together..still did not get it correct..I don't know what I am doing wrong, that was how I was shown it was done.
 

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J89 said:
Well we know that the y-axis is all together .5 volts, and the x-axis is 2 seconds..so it would common to just multiply .5 by 2.

Time scale is unrelated to the problem.

So I thought that in the graph since there are three tick marks, you would divide .5/3 and 2/3 and then multiply that together..still did not get it correct..I don't know what I am doing wrong, that was how I was shown it was done.

Your signal seems to be almost three ticks high, doesn't it? And there is 0.5V per tick, yes?

That's not different from using a ruler to measure something.
 

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