I have a project that involves a small motor, and the battery powering it would blow the motor in an instant without proper use of resistors. The battery I'm using is rated at 9.6 volts and 1600ma. The motor however, is rated at 3 volts and 0.3 Amps. I would like to go just under these ratings to be safe, so I'd like to provide 2.5 volts and 0.25ma. I've found a formula that's based off of a voltage divider circuit : Resistor 2 = [(Voltage out)(Resistor 1)]/(voltage in - voltage out). Using this formula (assuming my first resistor was 10k Ohms) I got(adsbygoogle = window.adsbygoogle || []).push({});

[(2.5)(10,000)]/(9.6-2.5)= 3,500 Ohms. This should provide the correct amount of resistance to get the voltage down to 2.5 volts. For calculating resistance for amperage, I used Resistance = Voltage/Current, and found 9.6/1600= 10. If the math was correct, and I used the right formula, this should be 10 ohms, but that is obismal and I'm pretty sure that's not right. If anyone knows how to make this circuit in a more efficient manner, or is able to double check that I'm using the right formulas, that would be greatly appreciated. By the way, I know the easiest answer is to just use a smaller battery, but this is part of a larger circuit, so I'm just trying to use the battery that's already in there. Thanks in advance

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# Limiting amps and volts from a battery

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