Volume Expansion: 15.5cm Sphere Heated from 40°C to 210°C

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Homework Help Overview

The discussion revolves around the volume expansion of a quartz sphere with a diameter of 15.5 cm when heated from 40°C to 210°C. Participants are exploring the application of the volume expansion formula and the necessary parameters for calculation.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the change in volume using the sphere's volume formula and the volume expansion formula. Questions arise regarding the correct interpretation of the temperature change and the value of the coefficient of volume expansion for quartz.

Discussion Status

Participants are actively discussing the calculation process, with some confirming the temperature change and others expressing difficulty in obtaining the correct answer. There is a focus on verifying the coefficient of volume expansion and its application in the formula.

Contextual Notes

There is mention of the coefficient of volume expansion for quartz, which is noted as 0.000001, and uncertainty regarding its application in the calculations. Participants are also questioning the correctness of the final volume change result.

ISU20CpreE
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A quartz sphere is 15.5 cm in diameter. What will be its change in
volume if it is heated from 40°C to 210°C?
Ok so what I did was use the diameter of the sphere and use the volume formula of the sphere and I got 15598.53 cm^3. Then what I did was use this formula [tex]\Delta(V) = \beta V_o\Delta(T)[/tex] knowing this formula I plug in the informationg given in the problem, but the part I don't understand is if its [tex]\Delta(T)[/tex] shouldn't it be the final tamperature minus the initial? Giving me 170 C. I can't do that part I need help.
 
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Yes, [tex]\Delta(T)[/tex] is the change in temperature, 170 degrees Centigrade. What do you mean you "can't do that part"? Have you looked up [itex]\beta[/itex] for quartz?
 
HallsofIvy said:
Yes, [tex]\Delta(T)[/tex] is the change in temperature, 170 degrees Centigrade. What do you mean you "can't do that part"? Have you looked up [itex]\beta[/itex] for quartz?
YEs i did but i really can't get the answer the Beta for quartz is 0.000001 i don't get the answer right. What can i do?
 
ISU20CpreE said:
YEs i did but i really can't get the answer the Beta for quartz is 0.000001 i don't get the answer right. What can i do?

I get 2.65 cm^3 as an answer.
 
ISU20CpreE said:
I get 2.65 cm^3 as an answer.

is this answer corect?
 

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