Volume of block given underwater and land weight

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SUMMARY

The problem involves calculating the volume of a metal block that weighs 9N in air and 7N in water, resulting in a correct volume of 200 cm³. The solution utilizes the principle of buoyancy, where the difference in weight (2N) corresponds to the weight of the water displaced by the block. By applying the equation for buoyancy and the density of water, the volume can be derived directly from the weight difference.

PREREQUISITES
  • Understanding of buoyancy principles
  • Knowledge of weight and mass relationships (w=mg)
  • Familiarity with density calculations (d=m/v)
  • Basic algebra for solving equations
NEXT STEPS
  • Study Archimedes' principle in detail
  • Learn how to calculate density using different materials
  • Explore applications of buoyancy in engineering
  • Practice solving similar buoyancy problems with varying weights
USEFUL FOR

Students in physics or engineering courses, educators teaching buoyancy concepts, and anyone interested in practical applications of fluid mechanics.

test2morrow
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Homework Statement



A block of metal weighs 9N in air and 7N in water. What is volume of block?

correct answer: 200cm^3

Homework Equations



w=mg
d=m/v



The Attempt at a Solution



I figured out that it has mass of 0.9kg on land...which may or may not be helpful.
 
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You know the difference in weights of the block when in different mediums. This is a buoyancy problem. The difference in weights is equal to the weight of water displaced by the block. If you use the density of water with the weight of water displaced you'll get the volume of the block.
 
thanks!
 

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