Volume of Triangle w/ xy-plane Vertices - Help Needed

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The discussion focuses on calculating the volume of a solid with a triangular base defined by the vertices (0,0), (1,0), and (0,1) in the xy-plane. The solid's cross sections, which are perpendicular to the y-axis, are equilateral triangles. The area of the triangular base is established as 1/2 bh, with the height of the equilateral triangles being derived from the relationship h = (sqrt(3)/4)(1-y), where x = 1 - y. The participants clarify the geometric properties of equilateral triangles to assist in solving the volume calculation.

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Question: Find the volume of the solid whose base is the triangular region of the xy-plane with vertices (0,0),(1,0),(0,1) and whose cross sections perpendicular to the y-axis are equilateral triangles.

I have the problem set up. just don't know how to get the cross sections of the triangles. i know the area is 1/2 bh i thought maybe similar triangles where the height would be sqrt(3)/4x and x=1-y. am i close? help
 
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gillyr2 said:
i know the area is 1/2 bh i thought maybe similar triangles where the height would be sqrt(3)/4x and x=1-y. am i close? help

Hi gillyr2! :smile:

yeah … close … :wink:

though I don't understand what you mean by "similar triangles" …

these are equilateral (3 x 60º) triangles of side (as you say) 1 - x …

so h = … ? :smile:
 

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