Did I Calculate the Volume Using Archimedes' Method Correctly?

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The volume of the sphere was calculated using the formula 4/3 pi r^3, resulting in 32/3 pi cm^3 for a radius of 2. The density of mercury was noted as 13.53 g/ml, leading to a calculated mass of 259.7 grams for the sphere. This mass was then used to determine the volume submerged in mercury, yielding 19.2 ml. A final suggestion was made to convert the volume from ml to cm^3 for completeness. Overall, the calculations appear to be correct with a minor conversion needed.
lc99
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Homework Statement


upload_2018-2-5_16-30-5.png


Homework Equations


Volume of Sphere = 4/3 pi r^3

d = m/v

The Attempt at a Solution


my attempt is:

r = 2
Vsphere = 32/3 pi cm^3
density of mercury = 13.53 g/ml

d*v of sphere = 259.7grams

259.7 grams of sphere * (1/density of mercury) = 259.7g *( 1 ml / 13.53 g) = 19.2 ml submerged

Did i do this correctly?
 

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Looks good to me.
 
The only thing left is, you need to convert your 19.2 ml to cm3. That shouldn't take very long.
 
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tnich said:
That shouldn't take very long.
:woot:
 

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