Water going down a waterfall, where is it warmer?

  • Thread starter Thread starter aeromat
  • Start date Start date
  • Tags Tags
    Water
Click For Summary
SUMMARY

The discussion focuses on calculating the temperature difference of water at the top and bottom of a 120m waterfall using the conservation of energy principle. The specific heat capacity of water is 4186 J/kg°C. By equating the potential energy at the top to the thermal energy at the bottom, the relationship can be established as mgh = mcΔT. This leads to the conclusion that the temperature increase of the water can be determined by the height of the fall and the specific heat capacity.

PREREQUISITES
  • Understanding of conservation of energy principles
  • Familiarity with specific heat capacity calculations
  • Basic knowledge of potential and kinetic energy equations
  • Ability to manipulate algebraic equations for thermal energy
NEXT STEPS
  • Study the derivation of the conservation of energy equation
  • Learn how to apply specific heat capacity in thermal calculations
  • Explore potential and kinetic energy transformations in physics
  • Investigate real-world applications of thermal energy in fluid dynamics
USEFUL FOR

Students studying physics, particularly those focusing on thermodynamics and energy conservation, as well as educators seeking to explain energy transformations in practical scenarios.

aeromat
Messages
113
Reaction score
0

Homework Statement


Consider a waterfall that is 120m high. How much warmer is the water at the bottom of the waterfall than at the top? The specific heat capacity of water is 4186J/ kg*°C.


Homework Equations


Conservation of Energy


The Attempt at a Solution



Eg [top] = Ek [just before the water hits the ground]
(m)(g)(h) = 1/2(m)(v)^2


I don't know how to compare the warmness of the top to the bottom, or how to get it calculation-wise. Does this have to do with:

E = (m)(c)(T)?
Where "E" is the heat energy?
 
Physics news on Phys.org
It's a straightforward conservation of energy.

(1) Potential energy before the fall > (2) Kinetic energy just before it hits > (3) Thermal energy in the water.

You can go straight from (1) to (3)
 
But would you mind giving me a hint as to how I would go about with the calculations?
 

Similar threads

  • · Replies 17 ·
Replies
17
Views
6K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 7 ·
Replies
7
Views
1K
Replies
13
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
17
Views
5K
  • · Replies 9 ·
Replies
9
Views
1K