Water-Oil Pressure: Calculating Pressure at 2000m Depth

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SUMMARY

The discussion focuses on calculating pressures in a hydrostatic scenario involving water and oil at a depth of 2000 meters. The water pressure (Pw) at this depth is calculated using the formula Ptotal = Patmosphere + Pfluid, resulting in Pw = 1.9701 x 10^7 kPa. It is established that the oil pressure (Po) at the same depth is equal to the water pressure, thus Po = 1.9701 x 10^7 kPa. Additionally, when the well bore is filled with oil (density = 800 kg/m³), the oil pressure at the top of the well bore is significantly higher than atmospheric pressure, explaining the phenomenon of oil gushers.

PREREQUISITES
  • Understanding of hydrostatic pressure principles
  • Familiarity with pressure equations, specifically Ptotal = Patmosphere + Pfluid
  • Knowledge of fluid densities, particularly water (1000 kg/m³) and oil (800 kg/m³)
  • Basic calculus for pressure calculations at varying depths
NEXT STEPS
  • Study hydrostatic pressure calculations in fluids
  • Learn about the properties of oil and water in subsurface reservoirs
  • Research the implications of pressure differences in oil extraction techniques
  • Explore the effects of fluid density on pressure calculations in various scenarios
USEFUL FOR

Students in engineering or geology, petroleum engineers, and anyone involved in fluid dynamics or reservoir management will benefit from this discussion.

slyman
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1Assume that below the surface of the Earth there is a connection between all of the ground water, and the water is static (the pressure profile is hydrostatic, you should know what this means in terms of water head). A hole is drilled (which fills with water) to a depth of 2000 m, where oil is found.
a) Call the surface of the Earth to be z=0 and assume this is the top of the water column. Find the water pressure (Pw) at a depth of 2000m.
b) Assume that at the reservoir, the water pressure is equal to the oil pressure (Po). Write down the oil pressure at z=2000 m.
c) Now assume that the well bore has its water displaced by the reservoir oil (density = 800 kg/m3), and then it is capped (we now have a column of static oil instead of a column of static water). Find the oil pressure at the top of the well bore (z= 0 m) and compare it to atmospheric pressure. (This is the simplest reason why there are gushers).




Homework Equations


Ptotal = Patmosphere + Pfluid

The Attempt at a Solution



for a) I got Ptotal= 1.01 * 10^5+ 1000*9.8*2000=1.9701*10^7 kpa = pw

b) I'm kind of confused here, so does this mean pw=poil so poil is the same answer as above

c) I don't have a clue.

I'm having a hard time understanding the question. Could somebody please clarify it for me? I'd appreciate your help. Thanks in advance.
 
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b) yes, it's the same. c) do the same thing you did in a) but use the density of oil instead of the density of water. Note that atmospheric pressure is much smaller than the other two. You can probably ignore it.
 

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