Water Rocket Project: Troubleshooting Answers & Explanations

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SUMMARY

The discussion centers on the calculations involved in a water rocket project, specifically determining the initial velocity (Vinitial), maximum height (Ymax), and maximum range. The calculated values are Vinitial = 28.8 m/s, Ymax = 42.3 m, and Range = 119.7 m, using the equations of motion under gravity. The participant seeks clarification on the role of water in propulsion and requests relevant formulas and diagrams related to horizontal projectile motion and free fall.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of projectile motion principles
  • Familiarity with basic trigonometry, specifically cosine functions
  • Concept of gravitational acceleration (9.8 m/s²)
NEXT STEPS
  • Research the physics of water propulsion in rockets
  • Learn about the equations of motion in projectile motion
  • Study the effects of different launch angles on range
  • Explore diagrams illustrating forces acting on a water rocket
USEFUL FOR

Students in physics courses, educators teaching projectile motion, and hobbyists interested in rocketry and fluid dynamics.

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1. Homework Statement
Hi, guys.
I did a project but questions are killing me right now.
I was going all the tutorials but I really have no idea.
What we did was water rocket project.
Here are the data
Ttotal - avg. 9.96 sec.
Avg. Apogee - 2.94 sec.


2. Homework Equations



3. The Attempt at a Solution


I need to find the v initial, ymax, and the maximum range.
Here is how I did it

For Vinitial
DeltaY(0) =(Vinitial)(5.88)+(1/2)(-9.8)(5.88)^2
Vinital = 28.8m/s
5.88sec comes from avg. apogeeX2 ------> (2.94)(2)

For Ymax,
Ymax= (Vinital)(time)+(1/2)(-9.8)(time)
(28.8)(2.94)+(1/2)(-9.8)(2.94)^2
= 42.3 m

For maximum Range,
I found out that cos 45 will give me maximum range so

Range=(Vinital)(cos45)(time)
(28.8)(cos45)(5.88)
= 119.7 m

Lastly, my teacher asked, "What role does the water play in making the rocket move?"
He also asked for relevant formulas and a diagram illustrating the forces.
Only thing we learned so far are Horizontal Projectil motion and free fall.
I do not think we ever learned this.
Can you please help me with this? I've been working for entire day!
Thanks guys.
 
Last edited:
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Oh, I realized I had to put what I did.
here is what I did..
for Vinitial,
I did
deltaY=(Vinitial)(5.58)+(1/2)(-9.8)(5.88)^2
and got Vinitial=28.8m/s.
5.88 comes from avg. apogee= 2.94X2=5.58

For Ymax,
I did
Ymax = (28.8)(2.94)+(1/2)(-9.8)(2.94)^2
Ymax = 42.3 m

Lastly, for Range
Since Range max, I found that cos 45 will give me maximum range
So,
Range=(Vinital)(cos45)(time)
(28.8)(cos45)(5.88)
Range=119.7m.

Here is how i did it.
But honestly,
on the last problem with "what role does the water play in making the rocket move?"
I abs. have no idea.
Thanx guys.
 

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