Understanding Wattage and Efficiency in Electrical Appliances: Explained

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SUMMARY

The discussion clarifies that the wattage rating on electrical appliances indicates the power input at the main components, calculated as Vrms multiplied by Irms. It emphasizes that this rating does not account for energy losses throughout the entire circuit, which are primarily manifested as heat due to resistance. The conversation also addresses misconceptions about power flow and dissipation, confirming that while power travels quickly, it is not a form of magnetic energy but rather a measure of electrical energy. Additionally, it highlights the importance of understanding power factor in relation to VA ratings and actual wattage.

PREREQUISITES
  • Understanding of electrical power concepts, including voltage (Vrms) and current (Irms).
  • Familiarity with the principles of resistance and heat generation in electrical circuits.
  • Knowledge of power factor and its implications on electrical appliances.
  • Basic comprehension of electrical measurements, including watts and volt-amperes (VA).
NEXT STEPS
  • Research the relationship between power factor and wattage in electrical systems.
  • Explore the concept of efficiency in electrical appliances and how it affects performance.
  • Learn about the differences between real power (watts) and apparent power (VA).
  • Investigate tools for measuring power factor in various electrical devices.
USEFUL FOR

Electrical engineers, technicians, and anyone involved in the design or analysis of electrical appliances will benefit from this discussion, particularly those interested in optimizing energy efficiency and understanding power measurements.

Mr_Bojingles
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In an ordinary electrical appliance they usually tell you the wattage of it on a tag. Does the wattage include all power loss throughout the whole circuit or does it only tell you the amount of power dissipated at the main components. For example say I have a flashlight. Would the wattage on the tag tell me how much energy is dissipated throughout the whole circuit (wires) or will it only tell me how much energy is dissipated at the resistor (light bulb).

I know they use the word "efficiency" to tell you how much energy is lost to resistance throughout the circuit.
 
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The wattage rating on the tag refers to the power input jack. So it is Vrms * Irms for the whole product.
 
Thanks a lot.
 
I have another quick question. Heres the explanation of power and watts in the book Teach Yourself Electricity and Electronics:

Whenever current flows through a resistance, heat results. This is inevitable. The heat
can be measured in watts, abbreviated W, and represents electrical power. Power can
be manifested in many other ways, such as in the form of mechanical motion, or radio
waves, or visible light, or noise. In fact, there are dozens of different ways that power
can be dissipated. But heat is always present, in addition to any other form of power in
an electrical or electronic device. This is because no equipment is 100-percent efficient.
Some power always goes to waste, and this waste is almost all in the form of heat.

I heard another explanation for power and watts which was confusing me. It explained that current flows in one direction from the negative terminal of the battery, does not dissipate at the resistor, and is measured in amperes. Power on the other hand travels at the speed of light from the power source to the resistor equally from both terminals and is dissipated at the resistor. It also explained that this power is not electricity but a form of magnetic energy measured in watts.

Is the second explanation accurate?
 
it is true. a battery has its curren flowing from both terminals, be t positive or negative. they can both be measured by the ammeter but the thing about dissipating the resistor I am not sure. but power does travel fast and is is not a form of electricity but a term used for amount of ... in a circuit.

... i haven't though of the word to be used yet.
 
Mr_Bojingles said:
I have another quick question. Heres the explanation of power and watts in the book Teach Yourself Electricity and Electronics:

Whenever current flows through a resistance, heat results. This is inevitable. The heat
can be measured in watts, abbreviated W, and represents electrical power. Power can
be manifested in many other ways, such as in the form of mechanical motion, or radio
waves, or visible light, or noise. In fact, there are dozens of different ways that power
can be dissipated. But heat is always present, in addition to any other form of power in
an electrical or electronic device. This is because no equipment is 100-percent efficient.
Some power always goes to waste, and this waste is almost all in the form of heat.


I heard another explanation for power and watts which was confusing me. It explained that current flows in one direction from the negative terminal of the battery, does not dissipate at the resistor, and is measured in amperes. Power on the other hand travels at the speed of light from the power source to the resistor equally from both terminals and is dissipated at the resistor. It also explained that this power is not electricity but a form of magnetic energy measured in watts.

Is the second explanation accurate?

What you quoted is reasonable. The other stuff is ridiculous garbage. Where did you see that?
 
I can't remember exactly where I heard it. It might have been from someone here. I probably misinterpreted what I read.
 
berkeman said:
The wattage rating on the tag refers to the power input jack. So it is Vrms * Irms for the whole product.

would that product Vrms x Irms be the VA which is bigger than the wattage if the power factor is less than one?

it's probably not a big deal for consumer appliances.
 
rbj said:
would that product Vrms x Irms be the VA which is bigger than the wattage if the power factor is less than one?

it's probably not a big deal for consumer appliances.

I believe that is correct, but I don't work much with power factor. To the extent that the power factor is less than 1, you don't dissipate the total VA power. But the source power supply generally needs to be capable of supplying the VA rating, I believe. Probably wikipedia.org would have a clearer answer about power factor considerations.
 

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