Wave Function: Normalization Constant

[teme92]

Ah there's still the $dx$ left:

$\frac{a}{2}+\frac{a}{2}=a$, therefore $A=\frac{1}{a}$

 

[George Jones]

Not quite. There is an A from psi, and another A from \bar{psi}.

 

[teme92]

$A=\frac{1}{\sqrt{a}}$?

 

[George Jones]

Looks okay.

 

[teme92]

Brilliant, and regarding the sketch part?

 

[George Jones]

What are $Re(e^{-i\theta})$ and $Im(e^{-i\theta})$?

 

[teme92]

$Re=\theta$ and $Im=-i$?

 

[George Jones]

No. Recall how $e^{i\theta}$ was expressed earlier in the thread.

 

[teme92]

Oh I get you. $Re=cos\theta$ and $Im=isin\theta$?