Wave-function solution of a rectangular-well potential

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The discussion centers on the potential error in the wave-function solution for a rectangular-well potential, specifically questioning the use of ##x## in the equation. It is suggested that ##x## should be replaced with a constant, such as ##\beta##, since energy ##E## is constant and independent of position. Participants also debate the clarity of the symbols used, particularly confusing the Greek letter kappa with the letter x due to the typeface. The conversation highlights the importance of precise notation in mathematical expressions. Overall, the thread emphasizes the need for accuracy in representing wave functions in quantum mechanics.
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Is the solution given below wrong?
Screen Shot 2015-12-13 at 8.29.04 am.png

Screen Shot 2015-12-13 at 8.29.15 am.png


I believe the ##x## in (25.2) is wrong; it should be replaced by a constant, such as ##\beta##, because ##E## is a constant and not dependent on ##x##.

Should the correct answer be
even solution:
Screen Shot 2015-12-13 at 8.17.51 am.png

odd solution:
Screen Shot 2015-12-13 at 8.18.02 am.png

where
Screen Shot 2015-12-13 at 8.18.24 am.png

Screen Shot 2015-12-13 at 8.18.43 am.png
 
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That is not an x but the greek letter kappa.
 
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PietKuip said:
That is not an x but the greek letter kappa.

I could hardly tell the difference!
 
That is a terrible typeface. I've never seen a kappa that looks like that! ?:)
 
PietKuip said:
That is not an x but the greek letter kappa.
To me it looks much more like the Hebrew letter aleph...
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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