Wave Functions in a Potential Well with infinite high walls

Click For Summary
SUMMARY

The discussion focuses on solving the time-dependent Schrödinger equation for a particle in a potential well with infinite high walls, where the potential V(x) is defined as V(x)=0 for -L/2 ≤ x ≤ +L/2 and V(x)=∞ elsewhere. The wave functions for the first two energy states are given as φ₁(x)=√(2/L)cos(π/L·x) and φ₂(x)=√(2/L)sin(2π/L·x). The initial wave function is expressed as ψ(x,0)=1/√2(φ₁(x)+φ₂(x)). Participants discuss how to derive the coefficients a₁(t) and a₂(t) by inserting ψ(x,t) into the time-dependent Schrödinger equation and obtaining the necessary integrals.

PREREQUISITES
  • Understanding of the Schrödinger equation and its applications in quantum mechanics.
  • Familiarity with wave functions and boundary conditions in quantum systems.
  • Knowledge of differential equations and their solutions.
  • Basic concepts of quantum mechanics, particularly potential wells and energy quantization.
NEXT STEPS
  • Study the derivation of coefficients in quantum mechanics, focusing on time-dependent wave functions.
  • Learn about the mathematical techniques for solving differential equations related to quantum systems.
  • Explore the implications of boundary conditions on wave functions in potential wells.
  • Investigate the normalization of wave functions and its importance in quantum mechanics.
USEFUL FOR

Students and professionals in physics, particularly those specializing in quantum mechanics, as well as educators looking to enhance their understanding of wave functions in potential wells.

Lunar_Lander
Messages
33
Reaction score
0

Homework Statement



Consider a potential well with infinite high walls, i.e. V(x)=0 for -L/2\leq x \leq +L/2 and V(x)=\infty at any other x.

Consider this problem (the first task was to solve the stationary Schroedinger equation, to get the Energies and Wave Functions, especially for n=1 and n=1, which gave \varphi_1=\sqrt{2/L}\cos(\pi/L\cdot x) and \varphi_2=\sqrt{2/L}\sin(2\pi/L\cdot x)) for the time-dependent Schroedinger Equation. At the time t=0, the wave function is given as \psi(x,0)=\frac{1}{\sqrt{2}}\varphi_1(x)+\frac{1}{\sqrt{2}}\varphi_2(x).

The further development of \psi(x,t) in time can be given as \psi(x,t)=a_1(t)\varphi_1(x)+a_2(t)\varphi_2(x). Determine the coefficients a_1(t), a_2(t).

For this, insert \psi(x,t) into the time dependent Schroedinger Equation and consider integrals of the form \int_{-\infty}^{infty}dx \varphi_m(x)... with m=1, 2. From that you will obtain a simple differential equation for each a1and a2, which you can solve easily with the boundary conditions given for t=0.

Homework Equations



Schroedinger Equations, other equations given above.

The Attempt at a Solution


I have first tried to follow the instructions and tried to insert the ψ into the Schroedinger Equation, which looked like this:

-\frac{\hbar^2}{2m}(a_1(t) \frac{d^2}{dx^2}\varphi_1(x)+a_2(t) \frac{d^2}{dx^2} \varphi_2(x))=i\hbar(a_1'(t)\varphi_1(x)+a_2'(t) \varphi_2(x))

But I have to admit that I do not know how to go on from there. How can I get those integrals that are mentioned in the problem? And how do I get the differential equations?
 
Physics news on Phys.org
First, you should get the left-hand side in terms of things you know (i.e. the energy values and \varphi).

This will give you an equation involving \varphi, a, a'. From here, you want to get rid of the \varphi, because you want an equation with just a and a'. Think of a way you could do this.
 

Similar threads

Replies
7
Views
2K
Replies
22
Views
3K
Replies
16
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
7
Views
3K
  • · Replies 19 ·
Replies
19
Views
2K
Replies
2
Views
2K
Replies
4
Views
5K
Replies
2
Views
2K
Replies
3
Views
2K