Two loudspeakers emit sound waves of the same frequency along the x-axis. The amplitude of each wave is . The sound intensity is minimum when speaker 2 is 10 cm behind speaker 1. The intensity increases as speaker 2 is moved forward and first reaches maximum, with amplitude 2 , when it is 30 cm in front of speaker 1. What is the phase difference between the two speakers.(adsbygoogle = window.adsbygoogle || []).push({});

phase difference=2*pi*deltax/wavelength+initial phase difference

I tried using this equation but I got the wrong answer. I said delta x was 30cm, wavelength is 80cm and initial phase difference is pi. Could anyone tell me where I am going wrong with this equation?

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# Wave interference of loudspeakers

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