Wavelength and Fundamental Frequency of Standing Wave on 2m String

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Homework Help Overview

The discussion revolves around a standing wave on a string that is 2 meters long, resonating at a frequency of 400 Hz with three antinodes. Participants are exploring the wavelength of the standing wave and the concept of fundamental frequency.

Discussion Character

  • Conceptual clarification, Assumption checking, Exploratory

Approaches and Questions Raised

  • Participants are attempting to determine the wavelength based on the number of antinodes and the length of the string. There are questions about the initial assumption that the wavelength is equal to the length of the string. Some participants suggest re-evaluating the drawn representation of the wave to clarify the wavelength.

Discussion Status

There is an ongoing exploration of the wavelength, with some participants suggesting that it may be 4/3 meters instead of 2 meters. The concept of fundamental frequency is being discussed, with prompts to visualize the string's vibration at this frequency to find its wavelength and frequency.

Contextual Notes

Participants are working within the constraints of the problem, specifically the fixed length of the string and the frequency provided. There is a focus on understanding definitions and relationships between wavelength and frequency without arriving at a definitive conclusion.

pooka
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A standing wave resonates at 400 Hz with three antinodes on a string tied tightly between two posts 2.0 meters apart.
What is the wavelength of this standing wave?
What is the fundamental frequency of this string?

I tried to draw the picture out, and it looks like the wavelength is just 2.0 m? I am not sure how to find the fundamental frequency though.
 
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Hi pooka,

pooka said:
A standing wave resonates at 400 Hz with three antinodes on a string tied tightly between two posts 2.0 meters apart.
What is the wavelength of this standing wave?
What is the fundamental frequency of this string?

I tried to draw the picture out, and it looks like the wavelength is just 2.0 m?

Before dealing with the fundamental frequency, I don't believe this wavelength is correct. If you look at it again, do you see what it is? Or if not, why did you choose 2m as the wavelength?
 
alphysicist said:
Hi pooka,



Before dealing with the fundamental frequency, I don't believe this wavelength is correct. If you look at it again, do you see what it is? Or if not, why did you choose 2m as the wavelength?

I chose this wavelength because when I drew the wave out, the post is 2 metres apart, so I thought that the wavelength would also be 2 metres.
 
Okay I just redrew the wave. Is the wavelength 4/3 metres then?
 
pooka said:
Okay I just redrew the wave. Is the wavelength 4/3 metres then?

That sounds right to me.

For your question in your original post, what is the definition of the fundamental frequency? Try drawing this string vibrating in its fundamental frequency (instead of the frequency they give you). Can you find its wavelength in that case? Does that help you find its frequency?
 
alphysicist said:
That sounds right to me.

For your question in your original post, what is the definition of the fundamental frequency? Try drawing this string vibrating in its fundamental frequency (instead of the frequency they give you). Can you find its wavelength in that case? Does that help you find its frequency?

Is the fundamental frequency wavelength 4 m then?
 
pooka said:
Is the fundamental frequency wavelength 4 m then?

Yes, that is the wavelength when it vibrates at its fundamental frequency.
 
thanks!
 
Sure, glad to help! (Just to be sure I understood the wording in one of your posts, you did use that 4m wavelength to find the fundamental frequency, right?)
 
  • #10
alphysicist said:
Sure, glad to help! (Just to be sure I understood the wording in one of your posts, you did use that 4m wavelength to find the fundamental frequency, right?)

Yup! The fundamental frequency is given by fn = v/λn.
I first found v by using the v = fλ where f is the 400 Hz times the wavelength 4/3

Then I divided the v by 4.
 

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