1. The problem statement, all variables and given/known data A string vibrates at its third-harmonic frequency. The displacement at a point 59.0cm from one end is the first time the displacement is half the maximum amplitude. How long is the string? 2. Relevant equations wavelength=(2(rope length))/nodes y=Asin(kx) k=2pi/wavelength 3. The attempt at a solution 0.5A=Asin(kx) kx=30 k(0.59m)=30 k=50.85 50.85=2pi/wavelength wavelength=0.1236m 0.1236m=(2(rope length))/3 rope length=0.1854m How is such a small rope length possible if 0.59m is half the distance from the first amplitude? What am I doing wrong?