Wavelength of Source in Loud Single Mirror Exp.

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Homework Help Overview

The discussion revolves around a loud single mirror experiment involving fringe widths and their relation to wavelength. The original poster presents a scenario where a bright fringe of width changes as the angle of incidence is altered, prompting a calculation of the wavelength of the source based on given measurements.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss how to determine the distance between the two slits and whether to use the incidence angle in their calculations. There is a focus on applying the provided equation for wavelength in two different scenarios.

Discussion Status

Some participants have offered guidance on using the wavelength equation in different contexts, while others are exploring the implications of their calculations. There appears to be a productive exchange of ideas, although no consensus on the final answer has been reached.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information available for solving the problem. The discussion includes questioning the assumptions related to the setup of the experiment and the definitions of terms used.

merc90
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1. Homework Statement : In a loud single mirror exp. a bright fringe of width 0.2 mm is seen at a point on the screen kept at a distance 1.0 m from the source. When the mirror is raised up to increase the angle of incidence at any point of the mirror by a dist. of 0.9 mm, fringe width of the same fringe becomes 0.5 mm, find the wavelength of the source.

2. Homework Equations : wavelength = distance between the two slits (a) * fringe width (X) / distance from source to screen (D)
3. The Attempt at a Solution : How to find the distance between the two slits? Should I be proceeding by finding "a" by a= incidence angle*D?
 
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merc90 said:
1. Homework Statement : In a loud single mirror exp. a bright fringe of width 0.2 mm is seen at a point on the screen kept at a distance 1.0 m from the source. When the mirror is raised up to increase the angle of incidence at any point of the mirror by a dist. of 0.9 mm, fringe width of the same fringe becomes 0.5 mm, find the wavelength of the source.

2. Homework Equations : wavelength = distance between the two slits (a) * fringe width (X) / distance from source to screen (D)

3. The Attempt at a Solution : How to find the distance between the two slits? Should I be proceeding by finding "a" by a= incidence angle*D?

Welcome to Physics Forums.

You can use the first equation you wrote,
wavelength = distance between the two slits (a) * fringe width (X) / distance from source to screen (D)
... and write it twice, because there are two situations:
(1) the distance between the "slits" is a
(2) the distance between the "slits" is ____ [where you fill in the blank here].
 
Thanks Redbelly98 for the quick reply.

Is the answer: wavelength = 6000 A correct?

Steps:
wavelength = 2*a*X/D
Therefore, 2*a*0.2/1000=2*(a-0.9)*0.5/1000
which gives, a=1.5 or 2*a = 3.0
so, wavelength =3.0*0.2/1000
=6000 A
 
Looks good!

You may need to better explain how you worked the units, if you submit your homework to be graded or have to work a similar problem on an exam someday.
 

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