Wavevector in infinite square well

Click For Summary
The discussion revolves around the confusion between two expressions for the wavevector (k) in an infinite square well: k = nπ/L and k = 2nπ/L. The correct expression depends on the boundary conditions applied to the wavefunction, which must vanish at the boundaries of the well. Typically, k = nπ/L is used when the well is defined with a width of L, while k = 2nπ/L applies when the well is effectively treated as having a width of 2L. The distinction arises from different definitions of the well's boundaries, which can lead to varying interpretations in different sources. Clarifying these definitions is essential for accurately applying the wavevector in quantum mechanics problems.
Master J
Messages
219
Reaction score
0
Right guys, I want to get this one straight...

We have all seen the simple infinite square well a million times. From it, we can get the condition for the k-vector of the electron that

k = n.pi / L

Now, I also come across all the time that k = 2n.pi / L

When do we use which boundary condition? They both seem to come from the same situation, but I cannot see when one is used?

It's a simple situation that's been bugging me a while! Hope someone can clear this up.

Cheers!
 
Physics news on Phys.org
The wave-function needs to disappear at the 2 boundaries, so whichever k produces the disappearing wave-function at the 2 boundaries is the k that you should use. Usually the problem is defined so that L is the total length of the square well, so you should use the first one. The second one would be used if the total length of the square well was, for some reason, 1/2L.
 
It would help if you could give us specific references to sites/books/whatever that do it each way, otherwise we have to guess.

My guess is that it's because some sources define the well as having width L, with either 0 < x < L or -L/2 < x < +L/2; and some define the well as having width 2L, with -L < x < L.
 
Did I get the lengths backwards...? Should it be L and 2L? My apologies if I did, I just tried to work it out in my head.
 
I can't actually think of any right now, I just know I've seen it come up. For instance, in deriving the Density of States from the Free Electron Model.

So you think it's just from the fact that one can define the width of the well as L or 2L?
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 28 ·
Replies
28
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K