Weak nuclear force - circumstances in which it is manifested

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SUMMARY

The weak nuclear force is indeed active in certain circumstances, such as beta decay, where neutrons can convert into protons. While it is true that free neutrons decay via the weak force, this interaction also occurs in bound neutrons within unstable nuclei, such as tritium, which can decay into helium-3. The discussion clarifies that the weak nuclear force is not limited to high-energy environments or radioactive materials but can manifest in specific isotopes under normal conditions, such as in a glass of water containing tritium.

PREREQUISITES
  • Understanding of weak nuclear force principles
  • Knowledge of beta decay processes
  • Familiarity with nuclear stability and isotopes
  • Basic concepts of particle physics
NEXT STEPS
  • Research the mechanisms of beta decay in various isotopes
  • Study the role of the weak nuclear force in nuclear reactions
  • Explore the properties and applications of tritium in nuclear physics
  • Learn about the differences between free and bound neutrons in nuclear decay
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Students and professionals in physics, particularly those focusing on nuclear physics, particle physics, and anyone interested in the fundamental forces of nature.

arlesterc
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I have a glass of water at room temperature. The electromagnetic force is at play between the electrons and nucleus of the atoms, the strong nuclear force is at play holding the nucleus together, the force of gravity weak as it may be is at play between the various particles - electrons, quarks. Is the weak nuclear force at play as well? Are neutrons being converted into protons in this glass as is the case with the weak nuclear force be it in a very minimal way/not frequent but still happening? Or is the case that the weak nuclear force only manifests itself in special circumstances such as radioactive materials, extremely high temperature/high energy situations - sun, accelerators? From my reading it seems to only occur to free standing neutrons - not those bound in a nucleus - which I assume to be a special circumstance/special environmental situation - and which is not the case with my glass of water at room temperature. Thanks in advance for clarification on this point.
 
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The weak nuclear force is involved in beta decay and similar processes (n to p or p to n inside nucleus). Water at room temperature will have beta decay only if there is tritium present, which decays to He3.
 
Thanks for the quick response. If tritium is present then somehow there ends up being unbound neutrons which decay into protons? I am asking because per this wiki note - https://en.wikipedia.org/wiki/Weak_interaction - "A particularly extreme example is the weak-force decay of a free neutron, which takes about 15 minutes." I thought the weak force only applied in the circumstances where there are free neutrons. Are you saying that bound neutrons - in the nucleus - an unstable nucleus - also have weak force decay? So in the nucleus of all radioactive elements the weak force is at work changing bound neutrons in the nucleus to protons? And the wiki example is not the general case that only free neutrons decay/exhibit the weak force?
 
arlesterc said:
I thought the weak force only applied in the circumstances where there are free neutrons.

This is not the case. Beta decays of nuclei like tritrium are weak force decays.
 

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