- #1

Henrybar

- 19

- 0

Not sure if my work/answer is correct

accelerating down (up is positive)

Fnet= Fn - Fg

ma = Fn - mg

(60)(-4)= Fn - (60)(-9.8)

-240 = Fn +588

Fn = -828

∴ Fn = 828 N(Down)

accelerating up (up is positive)

Fnet = Fn - Fg

240 = Fn +588

Fn = -348

∴Fn = 348 N(down)

Free fall: the weight of the student is the same as if he/she were standing on the ground(588N) since gravity is still present and the student's mass remains constant.