Weight of impact is from an object of 40kg that falls 50cm

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SUMMARY

The impact force of a 40kg object falling from a height of 50cm can be calculated using the formula for gravitational potential energy, e=mgh, where 'm' is mass, 'g' is acceleration due to gravity (9.8 m/s²), and 'h' is height. The velocity at impact is determined to be 3.13 m/s, calculated using kinematic equations. The deceleration upon impact varies significantly based on the surface material and geometry of both the falling object and the surface it strikes. Accurate impact force requires knowledge of the deceleration, which can be hundreds of g's for hard surfaces.

PREREQUISITES
  • Understanding of gravitational potential energy (e=mgh)
  • Familiarity with kinematic equations (D = 1/2*a*t², Vf = Vo + a*t)
  • Knowledge of Newton's second law (f=ma)
  • Basic physics concepts related to impact and deceleration
NEXT STEPS
  • Research the effects of surface material on impact force
  • Learn about calculating deceleration in impact scenarios
  • Explore advanced kinematic equations for varying conditions
  • Investigate the relationship between mass, velocity, and impact energy
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Physics students, engineers, safety analysts, and anyone interested in understanding the dynamics of falling objects and impact forces.

Jeanette
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Hi,

I have a basic question that i would be very thankful if someone could help me answer.

I need to find out what the weight of impact is from an object of 40kg that falls 50cm.

Many thanks.

Jeanette
 
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The force an object imparts at impact is extremely difficult to determine with math alone (and isn't constant throughout the impact anyway). It depends on the material properties and geometry of the object being dropped and the object being hit.

The best you can do with ease is impact energy, which for a dropped object far below terminal velocity is just e=mgh

If you know the deceleration, though, you can use f=ma. If you drop a hard object on a hard floor, the deceleration can be hundreds of g's.
 
I would first find the velocity at the moment of impact

D = 1/2*a*t^2
.5 = 1/2*9.8*t^2

t=.319

Vf = Vo + a*t^2
Vf = 0 + 9.8*.319 = 3.13 m/s

The time it takes to lose velocity (or acceleration) can depend upon what surface it's hitting, way it lands etc. as mentioned in the above post. But the force of impact will be the mass times the acceleration (velocity divided by time it takes to go from 3.13 m/s to 0 m/s). Hope this helped, and I also hope I didn't make a mistake on silly kinematics equations.
 

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