Weight of the whole earth with reference to an apple

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SUMMARY

The weight of the Earth with reference to an apple weighing 0.25 kg is 2.45 N, derived from the gravitational force acting on the apple. This calculation is based on Newton's laws, specifically the third law, which states that forces are equal and opposite. Therefore, the gravitational force exerted by the Earth on the apple is matched by the gravitational force exerted by the apple on the Earth, both measuring 2.45 N. Understanding this relationship clarifies the distinction between mass and weight in a gravitational context.

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I don't know the answer to this question but it may only require common sense:

Let's say an apple on the surface of the Earth weighs 0.25 Kg. Imagine the apple as the little Earth and the whole Earth on top of it. What is the weight of the Earth with reference to that apple?

I suspect the answer is 0.25 Kg also? If so, why? If not, then what is the correct answer and why?
 
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First kg is a unit of mass, and weight is a force. So a .25 kg apple in Earth's gravitational field would weigh 2.45 N. Since forces are equal and opposite (Newton's 3rd law) the weight of the Earth in the gravitational field of the apple would also be 2.45 N.
 
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