MHB Weight of Water on 180ft x 40ft Roof: Help Needed!

  • Thread starter Thread starter xerxies
  • Start date Start date
  • Tags Tags
    Water Weight
Click For Summary
To calculate the weight of water on a 180ft x 40ft roof with 2 inches of water, the volume is determined to be 1200 cubic feet. Using the weight density of water, approximately 62.3 lb/ft³, the total weight can be calculated by multiplying the volume by the density. This results in a total weight of 74,760 pounds. The discussion emphasizes understanding the calculation process rather than just receiving the final answer. Accurate calculations are essential for future reference and safety considerations.
xerxies
Messages
3
Reaction score
0
hopeing some one can help me...180ft x 40 ft x 2 inches of water ...what is weight of water on roof thanks to all who ponder this as i am sadly in need of help...should have stayed in school lol thanks again people...xerxies
 
Mathematics news on Phys.org
First, we need to find the volume of the water. The volume of a cuboid is simply the product of its length, width, and height:

$$V=\left(180\text{ ft}\right)\left(40\text{ ft}\right)\left(2\text{ in}\cdot\frac{1\text{ ft}}{12\text{ in}}\right)=1200\text{ ft}^3$$

Now, weight density $\rho$ is defined as follows (where $w$ is weight):

$$\rho\equiv\frac{w}{V}\implies w=\rho V$$

For water, we have:

$$\rho\approx 62.3\frac{\text{lb.}}{\text{ft}^3}$$

Can you proceed?
 
MarkFL said:
First, we need to find the volume of the water. The volume of a cuboid is simply the product of its length, width, and height:

$$V=\left(180\text{ ft}\right)\left(40\text{ ft}\right)\left(2\text{ in}\cdot\frac{1\text{ ft}}{12\text{ in}}\right)=1200\text{ ft}^3$$

Now, weight density $\rho$ is defined as follows (where $w$ is weight):

$$\rho\equiv\frac{w}{V}\implies w=\rho V$$

For water, we have:

$$\rho\approx 62.3\frac{\text{lb.}}{\text{ft}^3}$$

Can you proceed?
sorry i only have very limited schooling and need final answer as total wieght thanks so much
 
xerxies said:
sorry i only have very limited schooling and need final answer as total wieght thanks so much

Hello xerxies, MHB is a board which aims to help you find the answer by yourself. We could give you the answer but it wouldn't help if this came up again in future.

Mark has given you the total volume as 1200 ft³, the density 62.3 lb/ft³ and the formula for weight weight = volume * density

Thus to find the weight multiply 1200 ft³ x 62.3 lb/ft³

edit: Technically your figures are for the mass of water and not its weight although the two are used interchangeably. If you need to find the force of the water then let us know
 
thanks all who helped
 
I have been insisting to my statistics students that for probabilities, the rule is the number of significant figures is the number of digits past the leading zeros or leading nines. For example to give 4 significant figures for a probability: 0.000001234 and 0.99999991234 are the correct number of decimal places. That way the complementary probability can also be given to the same significant figures ( 0.999998766 and 0.00000008766 respectively). More generally if you have a value that...

Similar threads

Replies
3
Views
2K
  • · Replies 16 ·
Replies
16
Views
5K
Replies
35
Views
4K
Replies
9
Views
6K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
4K