1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Weight percent of Ge needed to yield alloy with x atoms/cm3

  1. Dec 2, 2008 #1
    1. The problem statement, all variables and given/known data
    Germanium forms a substitutional solid solution with silicon. Compute the weight percent of germanium that must be added to silicon to yield an alloy that contains 2.43e21 Ge atoms per cubic centimeter. The densities of pure Ge and Si are 5.32 and 2.33 g/cm3 respectively.

    2. Relevant equations
    not sure

    3. The attempt at a solution
    calculate Ge weight per atom:
    72.6/6.0221418e23 = 1.20555e-22

    calculate g/cm3 germanium in alloy
    1.20555e-22*2.43e21 = 2.92949e-1

    I'm not sure what to do next.
  2. jcsd
  3. Dec 2, 2008 #2


    User Avatar

    Staff: Mentor

    How many atoms of germanium per cubic centimeter in pure germanium?

    How many atoms of silicon per cubic centimeter in pure silicon?
  4. Dec 2, 2008 #3
    Ah, thanks Borek! I calculated the atoms per cc for Si and Ge as you said, subtracted the Ge atoms needed per cc from the Si since the Ge was the lower of the two, calculated the weight of both and used that to determine weight percent.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Similar Discussions: Weight percent of Ge needed to yield alloy with x atoms/cm3
  1. Percent Yield (Replies: 3)

  2. Percent Yield (Replies: 4)

  3. Percent Yield (Replies: 7)