Weight/Satellite Above Earth's Surface

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SUMMARY

The discussion focuses on calculating the weight of a 62.3 kg astronaut aboard a satellite orbiting 8.44 x 106 m above Earth. The gravitational acceleration at this altitude is calculated as 1.82 m/s2, leading to an initial weight calculation of 113 N. However, this value is incorrect due to the astronaut's state of free-fall in orbit, which results in an apparent weight of zero. The distinction between actual weight and apparent weight in a free-fall environment is crucial for accurate calculations.

PREREQUISITES
  • Understanding of gravitational force and Newton's law of universal gravitation
  • Familiarity with the concept of free-fall and orbital mechanics
  • Knowledge of the difference between actual weight and apparent weight
  • Basic proficiency in using gravitational equations, specifically GMe / r2
NEXT STEPS
  • Study the principles of orbital mechanics and the effects of gravity in orbit
  • Learn about the concept of apparent weight in free-fall scenarios
  • Explore the calculations involved in determining gravitational acceleration at various altitudes
  • Investigate the use of spring scales in measuring weight in non-inertial reference frames
USEFUL FOR

Physics students, aerospace engineers, and anyone interested in understanding the effects of gravity on objects in orbit.

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Satellite of mass 457 kg orbits at 8.44 x 10^6 m above earth.

What is weight of 62.3kg man in satellite?

Acceleration due to gravity created by Earth at distance of satellite = GMe / r^2 = 1.82m/s^2 ...this is RIGHT.

So to get weight of astronaut I multiplied 1.82 by 62.3 = 113N...but this is WRONG...can someone please advise why?
 
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sweetpete28 said:
Satellite of mass 457 kg orbits at 8.44 x 10^6 m above earth.

What is weight of 62.3kg man in satellite?

Acceleration due to gravity created by Earth at distance of satellite = GMe / r^2 = 1.82m/s^2 ...this is RIGHT.

So to get weight of astronaut I multiplied 1.82 by 62.3 = 113N...but this is WRONG...can someone please advise why?

No doubt that would be his weight if he were held stationary above the Earth at the given altitude, with no angular motion. But he is in orbit, and thus free-fall. If he were to place a spring scale between himself and the downward facing "floor" of the satellite, what do you suppose it would read?
 
sweetpete28 said:
Satellite of mass 457 kg orbits at 8.44 x 10^6 m above earth.

What is weight of 62.3kg man in satellite?

Acceleration due to gravity created by Earth at distance of satellite = GMe / r^2 = 1.82m/s^2 ...this is RIGHT.

So to get weight of astronaut I multiplied 1.82 by 62.3 = 113N...but this is WRONG...can someone please advise why?

Just checking that you considered the difference between the distance above the Earth [presumably the surface] and the Radius of the orbit - the distance to the centre of the Warth.

You are then faced with whether you are after the actual weight, or the apparent weight.
 

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