Weird question in "Vectors" chapter

  • Thread starter Thread starter Rijad Hadzic
  • Start date Start date
  • Tags Tags
    Vectors Weird
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
6 replies · 2K views
Rijad Hadzic
Messages
321
Reaction score
20

Homework Statement


Two aircraft approaching an aircraft carrier are detected by radar. The first aircraft is at a horizontal distance of 34.3 km in the direction 42 deg north of east. and has altitude 2.4 km

The second aircraft, at altitude 1.2 km, is at horizontal distance of 42.6 km in the direction 37 deg north of east.

What is the distance separating the two aircraft? Hint: use a coordinate system with the x-axis pointing east, the y-axis pointing north, and the z axis in the vertical direction

Homework Equations

The Attempt at a Solution


Ok I really don't understand the hint. it says the z axis in the vertical direction, correct me if I'm wrong but isn't north the vertical direction, which they said make the y axis?

And why do you even need an axis for this problem? Same with the angles.

I used the distance formula: [itex]((x_2 - x_1)^2 + (y_2 - y_1)^2 )^{1/2}[/itex]

plugging 42.6 as x_2 and 34.3 as x_1, 1.2 for y_2 and 2.4 for y_1

and got answer 8.38 km.

Book says answer is 9.02 km.

My doubts here are: first off, why would I need to use a 3 dimensional axis?

Second off, I used arc tan to check the angles and they seem off.

For example, on aircraft 1 I did arctan(2.4/34.3) and got 4 degrees, not even close to their stated 42 degrees.

Anyone have any clue? My book is starting to piss me off cause if you've been following the last two questions I asked on here apparently my book was wrong as well, I really want to complain to the author and I question why this was used in an introductory physics course cause I don't feel like I'm learning the material right because of all the contradictions.

Sorry for venting just had to get that off of my chest, and if i am indeed wrong I'm just going to look dumb for complaining lol.

Anyways can anyone please help me.
 
Physics news on Phys.org
Say then, you use the x and y coordinates in the horizontal plane to describe the displacements (from the origin).
How can you describe the altitude without using a z (vertical axis)?
 
J Hann said:
Say then, you use the x and y coordinates in the horizontal plane to describe the displacements (from the origin).
How can you describe the altitude without using a z (vertical axis)?

Wouldn't horizontal distance be on the x-axis and altitude be vertical distance?
 
Rijad Hadzic said:
first off, why would I need to use a 3 dimensional axis?
Because you've been given the locations in 3 dimensions.
Rijad Hadzic said:
correct me if I'm wrong but isn't north the vertical direction, which they said make the y axis?
Imagine yourself standing on the ground facing north. So, y-axis is going straight ahead (along north), x-axis is going to your right (east) and z axis is going towards the sky (vertically upward).
 
cnh1995 said:
Because you've been given the locations in 3 dimensions.

Imagine yourself standing on the ground facing north. So, y-axis is going straight ahead (along north), x-axis is going to your right (east) and z axis is going towards the sky (vertically upward).
alright I think I'm starting to get it. I'm going to work it again and come back if I need any help..
 
Looks like I'm going to have to use the distance formula with 3 variables..
 
  • Like
Likes   Reactions: Chestermiller
Got the correct answer guys.

Main thing I learned this problem:

I have a one track thought, I need to try harder to dig for the answer. They even gave me a hint yet I still thought that my way was right. I need to stop looking for help and basically try to understand the question better on my own.
 
  • Like
Likes   Reactions: Tom.G and cnh1995