- #1

eleventhxhour

- 74

- 0

\(\displaystyle \frac{x^2-5xy+4y^2}{x^2+3xy-28y^2} ⋅ \frac{x^2+2xy+y^2}{x^2-y^2} \)

I'm not really sure what a good process would be to simplify this. This is what I tried to do, (below) which is wrong. Could anyone point out what I did wrong and what a better process to simplify it would be? Thanks!

My answer:

\(\displaystyle \frac{-5xy+4y^2}{3xy-28y^2} ⋅ \frac{2xy + y^2}{-y^2}\)

\(\displaystyle \frac{-10x^2y^2 + 4y^4}{-3xy^3+28y^4}\)

\(\displaystyle \frac{2y^2(-5x^2+2y^2}{y^3(-3x+28y)}\)

And then I'm not sure what to do.