Ok, I have used every calculator I can find, typed it in several different ways for the past three hours and at this point I am giving up and asking for help. 1. The problem statement, all variables and given/known data A rock is thrown from the edge of a 14 meter high cliff with a velocity of total magnitude of 7m/s. Find the final velocity with which the rock hits the ground if it was launched initially upward. 2. Relevant equations OK so we have delta D - 14m (downward, negative) V1 - 7m/s V2 - Solve for A - 9.8m/s^2 (down) (let upward be positive so this would be negative) delta T - Solve for. For equations - (upward throw) Vfinal^2 = Vinitial^2+2AD Vfinal^2 = 7^2 + 2 (-9.8^2)(-14) So V final = square root ( (7^2) + 2(9.8^2)(-14) Final answer I got is 52.32. This is a practice question so they list the answer and the answer is supposedly plus or minus 17.98m/s. What am I doing wrong???!?!? I thought maybe calculator when squaring a negative number does not turn it into a positive (ie. -9.8x-9.8 = positive number) and therefore threw off answer but when done that way it is multiplied with negative 17 and I cannot ask for square root of a negative.. Been trying to troubleshoot this too long and its driving me nuts! Any and all help is SO appreciated.