What Am I Missing About the Centroid Equation for a Circular Segment?

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The discussion focuses on finding the centroid of a circular segment using the equation \(\bar{y}=\frac{4Rsin^3\frac{\theta}{2}}{3(\theta-sin\theta)}\). The user attempts to apply this formula for a circular segment with a diameter of 1 inch and an angle of 60°, resulting in an unexpectedly small centroid distance. Concerns are raised about whether the calculations are correct, especially since a different formula for a semicircle yields reasonable results. It is noted that the angle should be expressed in radians, as 60 degrees is equivalent to \(\pi/3\) radians, which could impact the calculations. The discussion highlights the importance of proper unit conversion in centroid calculations.
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Homework Statement



I need to find the centroid of a circular segment. I know nothing of calculus, and this is part of an analysis for statics that goes beyond the material covered in class.


Homework Equations



I've seen this equation for calculating the centroid:

\bar{y}=\frac{4Rsin^3\frac{\theta}{2}}{3(\theta-sin\theta)}

Please the Wiki link for the diagram:
http://en.wikipedia.org/wiki/File:Circularsegment_centroid.svg


The Attempt at a Solution



For a circle of 1 inch diameter, with an angle of 60°:

4(0.5")sin(30)^3= 0.25

divided by:

3(60-sin60)≈ 177.4

Answer: approximately 0.001"

Surely the centroid should be within the segment? Separately, I've found the centroid of a semicircle using:

\bar{y}=\frac{4R}{3\pi}

which gave reasonable results. I'm led to believe the first equation should give the correct centroid position for a semicircle (θ=180°), but I also got a very small distance for that, too.

What am I missing about the first equation?

Thanks.







 
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θ should be expressed in radians. 60 degrees is π/3 radians.
 
Very gently stated. :)

Thanks, Chester!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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