What Am I Missing About the Centroid Equation for a Circular Segment?

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SUMMARY

The discussion focuses on calculating the centroid of a circular segment using the equation \(\bar{y}=\frac{4R\sin^3\frac{\theta}{2}}{3(\theta-\sin\theta)}\). The user attempts to find the centroid for a circular segment with a diameter of 1 inch and an angle of 60°, resulting in an incorrect value due to the angle being expressed in degrees instead of radians. The correct approach requires converting 60° to \(\frac{\pi}{3}\) radians. Additionally, the user compares this with the centroid of a semicircle, which is calculated using \(\bar{y}=\frac{4R}{3\pi}\).

PREREQUISITES
  • Understanding of circular segments and centroids
  • Familiarity with trigonometric functions, specifically sine
  • Basic knowledge of radians and degrees conversion
  • Experience with calculus concepts, particularly in statics
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  • Learn about the derivation of the centroid formula for circular segments
  • Study the conversion between degrees and radians in mathematical calculations
  • Explore the application of centroids in engineering statics
  • Investigate the centroid calculation for other geometric shapes
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Students in engineering or physics, particularly those studying statics and needing to calculate centroids for various shapes, as well as educators looking for practical examples of centroid calculations.

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Homework Statement



I need to find the centroid of a circular segment. I know nothing of calculus, and this is part of an analysis for statics that goes beyond the material covered in class.


Homework Equations



I've seen this equation for calculating the centroid:

\bar{y}=\frac{4Rsin^3\frac{\theta}{2}}{3(\theta-sin\theta)}

Please the Wiki link for the diagram:
http://en.wikipedia.org/wiki/File:Circularsegment_centroid.svg


The Attempt at a Solution



For a circle of 1 inch diameter, with an angle of 60°:

4(0.5")sin(30)^3= 0.25

divided by:

3(60-sin60)≈ 177.4

Answer: approximately 0.001"

Surely the centroid should be within the segment? Separately, I've found the centroid of a semicircle using:

\bar{y}=\frac{4R}{3\pi}

which gave reasonable results. I'm led to believe the first equation should give the correct centroid position for a semicircle (θ=180°), but I also got a very small distance for that, too.

What am I missing about the first equation?

Thanks.







 
Physics news on Phys.org
θ should be expressed in radians. 60 degrees is π/3 radians.
 
Very gently stated. :)

Thanks, Chester!
 

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