What Are Different Ways to Define Energy in Physics?

AI Thread Summary
Energy in physics can be defined using various equations, with the joule being a derived unit represented as Newtons multiplied by meters, Coulombs multiplied by volts, or Watts multiplied by seconds. The joule is equivalently expressed in base units as meters squared times kilograms times seconds to the power of negative two. Dimensional analysis is crucial for understanding the SI unit representation of the joule, as demonstrated by the equation W = Fd. This equation facilitates the comparison of units on both sides, confirming the relationship between work and energy. Clarification on unit analysis can help in grasping these concepts more effectively.
gurrkin
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Hey. Here are the questions I'm a bit stuck on:

1) The joule is not a base unit. There are several equations which could be used to define the physical quantity energy. Find at least two of them

2) Use one of the equations you have foundnto find the combination of base units equivalent to the joule.

I have searched the internet but cannot find any relevant answers?


I think it is along these lines, but I am not sure:

The joule is equal to:
Newtons * metres
Coulombs * volts
Watts * seconds

The joule is also equivalent to:
metres^2 * kilograms * seconds^-2

Any help and clarification would be much appreciated - thank you.
 
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You need to write equations down that express some kind of energy. For example, what equation has something that is measured in Joules on the left side and Newtons*metres on the other. Do the same for the other two products of nits that you have listed.
 
Hi. Thanks for your reply! What does the second question mean though? I'm struggling to understand. Thanks again.
 
gurrkin said:
The joule is also equivalent to:
metres^2 * kilograms * seconds^-2
That is more or less the answer to your second part :)
It is actually asking you to use dimensional/units analysis to determine the SI unit representation of the Joule. For instance with the equation W = Fd, by comparing the units on both sides of the equation, you can arrive at the SI units equivalent of the joule
 
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