MHB What are f(0), f(1), and f(-1) in the equation f(x)= 2x^2- 3x+ 7?

  • Thread starter Thread starter mathdad
  • Start date Start date
AI Thread Summary
In the equation f(x) = 2x^2 - 3x + 7, the value of c is determined to be 7 from f(0). The values of a and b are found by solving the equations derived from f(1) = 6 and f(-1) = 12, resulting in a = 2 and b = -3. The function can be confirmed by substituting these values back into the original equation. The calculated values for f(0), f(1), and f(-1) are consistent with the derived coefficients. The discussion emphasizes the satisfaction of solving the math problem.
mathdad
Messages
1,280
Reaction score
0
Given f(x) = ax^2+bx+c, where a, b and c are constants, if f(0)=7,what is the value of c? Given that f(1)=6 and f(-1)=12, find the value of a and b.

My Work:

f(0) = 7

7 = a(0)^2 + b(0) + c

7 = 0 + 0 + c

7 = c

f(1) = 6

6 = a(1)^2 + b(1) + 7

6 = a + b + 7

6 - 7 = a + b

- 1 = a + b...Equation A

f(-1) = 12

12 = a(-1)^2 + b(-1) + 7

12 = a - b + 7

12 - 7 = a - b...Equation B

Equations A and B produce a system of equations.

- 1 = a + b...Equation A
12 - 7 = a - b...Equation B

Solving the system of equations for a and b, I found a to be 2 and b to be -3.

Is this correct?
 
Mathematics news on Phys.org
It's easy to check it yourself, isn't it? You are saying that a= 2, b= -3 and c= 7 so you are saying that f(x)= 2x^2- 3x+ 7. So, using that formula, what are f(0), f(1), and f(-1)?
 
HallsofIvy said:
It's easy to check it yourself, isn't it? You are saying that a= 2, b= -3 and c= 7 so you are saying that f(x)= 2x^2- 3x+ 7. So, using that formula, what are f(0), f(1), and f(-1)?

Ok.

- - - Updated - - -

HallsofIvy said:
It's easy to check it yourself, isn't it? You are saying that a= 2, b= -3 and c= 7 so you are saying that f(x)= 2x^2- 3x+ 7. So, using that formula, what are f(0), f(1), and f(-1)?

Ok. It feels good to solve a math problem.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...
Thread 'Imaginary Pythagoras'
I posted this in the Lame Math thread, but it's got me thinking. Is there any validity to this? Or is it really just a mathematical trick? Naively, I see that i2 + plus 12 does equal zero2. But does this have a meaning? I know one can treat the imaginary number line as just another axis like the reals, but does that mean this does represent a triangle in the complex plane with a hypotenuse of length zero? Ibix offered a rendering of the diagram using what I assume is matrix* notation...
Back
Top