- #1
Roodles01
- 128
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A little behind in this subject, but I understand raising & lowering operators to almost be factors of the Hamiltonian operator.
raising - Ahat dagger = 1/√2 (x/a - a*(δ/δx))
lowering - Ahat = 1/√2 (x/a + a*(δ/δx))
I also have the Hamiltonian as;
Hhat = (Ahat dagger * Ahat + 1/2) hbar ω0
Is this an identity defining the Hamiltonian?
Help!
A little pointer in the right direction or an explanation to provide a bit of clarity would be great.
Thank you.
raising - Ahat dagger = 1/√2 (x/a - a*(δ/δx))
lowering - Ahat = 1/√2 (x/a + a*(δ/δx))
I also have the Hamiltonian as;
Hhat = (Ahat dagger * Ahat + 1/2) hbar ω0
Is this an identity defining the Hamiltonian?
Help!
A little pointer in the right direction or an explanation to provide a bit of clarity would be great.
Thank you.