What Are the Chances of 6 Teams Winning Both Games in a Lawn Bowls Tournament?

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SUMMARY

The discussion centers on calculating the probability of 6 teams winning both games in a lawn bowls tournament involving 14 teams across 7 rinks. Each team plays two games, with the assumption that each game is a fair Bernoulli trial, meaning each team has a 50% chance of winning. The probability of exactly 6 teams winning both games can be derived using binomial probability formulas, considering the total number of teams and the outcomes of the games.

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  • Understanding of Bernoulli trials and their properties
  • Familiarity with binomial probability distributions
  • Basic knowledge of random variables
  • Concept of combinatorial mathematics
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  • Study binomial probability formulas and their applications
  • Learn about combinatorial mathematics for calculating combinations
  • Explore the concept of random variables in probability theory
  • Investigate fair game assumptions in probability and statistics
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This discussion is beneficial for statisticians, mathematicians, and anyone interested in probability theory, particularly in the context of game theory and sports analytics.

plato13
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hi all,

any help would be appreciate.

In a game of lawn balls:
7 rinks
2 teams per rink.
a total of 14 teams

after the first round of games the teams switch randomly
and play another round of games.

every team has played two games each.

Normally at the end of the two games there are 2, maybe 3 teams who have won both games.

What are the odds & the probability that 6 teams have won two games?

thanks,
P
 
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Are we assuming that each game is a fair Bernoulli trial? That is, either team wins with probability .5? Also, have you learned random variables yet? This will effect the way the answer should be explained.
 

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