What are the fields produced around a current carrying conductor?

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The E is the field within the superconductor, not just at the ends, but at any point within.

For the fields outside the conductor you would need to solve Maxwell's equations. I believe that there would also be no E-field outside of a superconducting wire, unless imposed externally, but I cannot justify that at the moment.
 
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DaleSpam said:
For the fields outside the conductor you would need to solve Maxwell's equations. I believe that there would also be no E-field outside of a superconducting wire, unless imposed externally, but I cannot justify that at the moment.

Anyway, thank you for the info on the fields within the current carrying conductors.

I look forward if anyone wants to reply for the actual question. I quote it once again:

Godparicle said:
If we consider a current carrying conductor, every instant an electron enters the conductor, another electron will be leaving the conductor. Thus, the current carrying conductor will not be charged (i.e, it would not have any net positive or negative charge). Remember dipole has zero net charge, but it does have electric field around it. So, if net charge is zero, it doesn't mean there is no electric field.

It is important to notice that, if we assume only electrons to be moving, and kernels (positive nuclei) to be static, magnetic field will be produced only due to electrons.

Does it mean that electric field and magnetic field exists around the current carrying conductor?
Or
Does it mean that only magnetic field exists around the current carrying conductor?

The question is simple, but I have found varied answers until now.
 
Yes, I was intrigued by some of the results, particularly the Poynting vector. It seems that in a very reasonable sense power doesn't flow through a wire.